下列方程的解分別是:
(1)x-1x+1+2x1-x2=0x1=2+3,x2=2-3x1=2+3,x2=2-3.
(2)x+3x2-3x+2+x+2x2-4x+3=x+1x2-5x+6x1=23,x2=-23x1=23,x2=-23.
(3)2(x+1x)2-3(x+1x)-5=0x1=2,x2=12x1=2,x2=12.
(4)1x2-2x-1+2x2-2x-2=3x2-2x-3x1=2+102,x2=2-102x1=2+102,x2=2-102.
(5)1x-1-1x-2=1x-6-1x-7x=4x=4.
(6)x-8x-10+x-4x-6=x-5x-7+x-7x-9x=8x=8.
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【答案】;;;;x=4;x=8
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【解答】
【點評】
聲明:本試題解析著作權屬菁優網所有,未經書面同意,不得復制發布。
發布:2025/5/29 4:0:1組卷:20引用:1難度:0.9
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