方程組x+y+z=100(1) x3+3y+5z=100(2)
的非負整數解為x=84 y=4 z=12
,x=81 y=11 z=8
,x=78 y=18 z=4
,x=75 y=25 z=0
x=84 y=4 z=12
,x=81 y=11 z=8
,x=78 y=18 z=4
,x=75 y=25 z=0
.
x + y + z = 100 ( 1 ) |
x 3 + 3 y + 5 z = 100 ( 2 ) |
x = 84 |
y = 4 |
z = 12 |
,
x = 81 |
y = 11 |
z = 8 |
,
x = 78 |
y = 18 |
z = 4 |
,
x = 75 |
y = 25 |
z = 0 |
x = 84 |
y = 4 |
z = 12 |
,
x = 81 |
y = 11 |
z = 8 |
,
x = 78 |
y = 18 |
z = 4 |
,
x = 75 |
y = 25 |
z = 0 |
【考點】解三元一次方程組.
【答案】
x = 84 |
y = 4 |
z = 12 |
,
x = 81 |
y = 11 |
z = 8 |
,
x = 78 |
y = 18 |
z = 4 |
,
x = 75 |
y = 25 |
z = 0 |
【解答】
【點評】
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發布:2024/5/27 14:0:0組卷:114引用:1難度:0.9
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